# C Exercises: Count all possible paths from top left to bottom right of a m X n matrix

## C Array: Exercise-85 with Solution

Write a program in C to count all possible paths from top left to bottom right of a m X n matrix.

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
// Function to count all possible paths from top-left to bottom-right in a matrix of size m x n
int PathCounting(int m, int n)
{
int ctr[m][n]; // Define a matrix to store path counts
// Initialize the leftmost column elements to 1 (only one way to reach each cell in the leftmost column)
for (int i = 0; i < m; i++)
{
ctr[i][0] = 1;
}
// Initialize the top row elements to 1 (only one way to reach each cell in the top row)
for (int j = 0; j < n; j++)
{
ctr[0][j] = 1;
}
// Calculate the number of paths for each cell in the matrix
for (int i = 1; i < m; i++)
{
for (int j = 1; j < n; j++)
{
ctr[i][j] = ctr[i - 1][j] + ctr[i][j - 1]; // Number of paths to reach current cell = paths from left + paths from top
}
}
return ctr[m - 1][n - 1]; // Return the number of paths to reach the bottom-right cell
}
int main()
{
int p, q;
p = 4; // Number of rows in the matrix
q = 4; // Number of columns in the matrix
printf("The size of matrix is: %d, %d\n", p, q);
printf("The all possible paths from top left to bottom right is: %d\n", PathCounting(p, q));
return 0;
}
```

Sample Output:

The size of matrix is : 4 x 4 The all possible paths from top left to bottom right is: 20

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