C Exercises: Find the equilibrium index of an array

C Array: Exercise-86 with Solution

Write a program in C to find the equilibrium index of an array.

Sample Solution:

C Code:

#include <stdio.h>

void findEquiIndex(int arr1[], int n)
{
    int sumofleft[n];
    sumofleft[0] = 0;
    for (int i = 1; i < n; i++) 
	{
        sumofleft[i] = sumofleft[i - 1] + arr1[i - 1];
    }
    int sumofright = 0;
    for (int i = n - 1; i >= 0; i--)
    {
        if (sumofleft[i] == sumofright) 
		{
            printf("%d  ",i);
        }
        sumofright += arr1[i];
    }
}

int main()
{
    int arr1[] = { 0, -4, 7, -4, -2, 6, -3, 0 };
    int n = sizeof(arr1) / sizeof(arr1[0]);
    int i;
   //------------- print original array ------------------	
	printf("The given array is:  \n");
	for(i = 0; i < n; i++)
		{
			printf("%d  ", arr1[i]);
		}
	printf("\n");
//-----------------------------------------------------------	
    printf("The equilibrium index found at : ");
    findEquiIndex(arr1, n);
    return 0;
}

Sample Output:

The given array is:  
0  -4  7  -4  -2  6  -3  0  
The equilibrium index found at : 7  5  0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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