C Exercises: Rotate the elements of a given array of integers in left direction and return the new array
C-programming basic algorithm: Exercise-37 with Solution
Write a C program to rotate the elements of a given array of integers (length 4 )in left direction and return the new array.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int a1[] = {10, 20, 30, 40};
arr_size = sizeof(a1)/sizeof(a1[0]);
printf("Elements in original array are: ");
print_array(a1, arr_size);
int result[] = { a1[1], a1[2], a1[3], a1[0] };
arr_size = sizeof(result)/sizeof(result[0]);
printf("\nElements in new array are: ");
print_array(result, arr_size);
}
print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
printf("%d, ", parray[i]);
}
printf("%d ", parray[i]);
printf("\n");
}
Sample Output:
Elements in original array are: 10, 20, 30, 40 Elements in new array are: 20, 30, 40, 10
Pictorial Presentation:
Flowchart:

C Programming Code Editor:
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C Programming: Tips of the Day
Why doesn't a+++++b work?
printf("%d",a+++++b); is interpreted as (a++)++ + b according to the Maximal Munch Rule!.
++ (postfix) doesn't evaluate to an lvalue but it requires its operand to be an lvalue.
! 6.4/4 says the next preprocessing token is the longest sequence of characters that could constitute a preprocessing token"
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