﻿ C : Array with middle elements of the 2 arrays, of length 5

# C Exercises: Create a new array containing the middle elements from the two given arrays of integers, each length 5

## C-programming basic algorithm: Exercise-39 with Solution

Write a C program to create a new array containing the middle elements from the two given arrays of integers, each length 5.

C Code:

``````#include <stdio.h>
#include <stdlib.h>s

int main(void){
int arr_size;
int a1[] = {10, 20, -30, -40, 30 };
int a2[] = {10, 20, 30, 40, 30};
int arr_size1 = sizeof(a1)/sizeof(a1[0]);
int arr_size2 = sizeof(a2)/sizeof(a2[0]);
printf("Elements in original array are:\n");
print_array(a1, arr_size1);
print_array(a2, arr_size2);
int result[] = { a1[2], a2[2]  };
arr_size = sizeof(result)/sizeof(result[0]);
printf("Elements in new array are: ");
print_array(result, arr_size);
}
print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
printf("%d, ", parray[i]);
}
printf("%d ", parray[i]);
printf("\n");
}
``````

Sample Output:

```Elements in original array are:
10, 20, -30, -40, 30
10, 20, 30, 40, 30
Elements in new array are: -30, 30
```

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Flowchart:

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## C Programming: Tips of the Day

Why doesn't a+++++b work?

printf("%d",a+++++b); is interpreted as (a++)++ + b according to the Maximal Munch Rule!.

++ (postfix) doesn't evaluate to an lvalue but it requires its operand to be an lvalue.

! 6.4/4 says the next preprocessing token is the longest sequence of characters that could constitute a preprocessing token"

Ref : https://bit.ly/3fdldUT