﻿ C Program: Create an array of 3 integers from an array

# C Exercises: Check a given array of integers of length 3 and create a new array

## C-programming basic algorithm: Exercise-44 with Solution

Write a C program to check a given array of integers of length 3 and create a new array. If there is a 5 in the given array immediately followed by a 7 then set 7 to 1.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'print_array'
void print_array(int parray[], int size);

int main(void){
// Declaration and initialization of variables
int arr_size;
int array1[] = {1, 5, 7};

// Calculating the size of the array
arr_size = sizeof(array1)/sizeof(array1[0]);

// Printing elements in the original array
printf("Elements in original array are: ");
print_array(array1, arr_size);

// Loop through the array to check for specific condition and modify elements
for (int i = 0; i < arr_size - 1; i++)
{
if (array1[i] == 5 && array1[i + 1] == 7)
array1[i + 1] = 1;
}

// Printing elements in the modified array
printf("Elements in new array are: ");
print_array(array1, arr_size);
}

// Definition of the 'print_array' function
void print_array(int parray[], int size)
{
int i;
for( i=0; i<size-1; i++)
{
// Printing each element with a comma and a space
printf("%d, ", parray[i]);
}
// Printing the last element without a comma and space
printf("%d ", parray[i]);
// Printing a new line to separate the elements
printf("\n");
}
``````

Sample Output:

```Elements in original array are: 1, 5, 7
Elements in new array are: 1, 5, 1
```

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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