C Exercises: Check a given array of integers and return true if the array contains 10 or 20 twice

C-programming basic algorithm: Exercise-43 with Solution

Write a C program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int nums[], int size);

int main(void){
    // Declaration and initialization of variables
    int arr_size;
    int array1[] = {12, 20};

    // Calculating the size of the array
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of calling 'test' function with the first array
    printf("%d", test(array1, arr_size));

    int array2[] = {20, 20};
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of calling 'test' function with the second array
    printf("\n%d", test(array2, arr_size));

    int array3[] =  {10};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of calling 'test' function with the third array
    printf("\n%d", test(array3, arr_size));
}       

// Definition of the 'test' function
int test(int nums[], int size)
{
    // Checking if the size is 2 and if the elements meet specific conditions
    return size == 2 &&
           ((nums[0] == 10 && nums[1] == 10) || (nums[0] == 20 && nums[1] == 20));
}

Sample Output:

0
1
0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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