﻿ C Program: Check if an array contains twice 10 or 20

C Exercises: Check a given array of integers and return true if the array contains 10 or 20 twice

C-programming basic algorithm: Exercise-43 with Solution

Write a C program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.

C Code:

``````#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {12, 20};
arr_size = sizeof(array1)/sizeof(array1[0]);
printf("%d",test(array1, arr_size));
int array2[] = {20, 20};
arr_size = sizeof(array2)/sizeof(array2[0]);
printf("\n%d",test(array2, arr_size));
int array3[] =  {10};
arr_size = sizeof(array3)/sizeof(array3[0]);
printf("\n%d",test(array3, arr_size));
}
int test(int nums[], int size)
{
return size == 2
&& ((nums[0] == 10 && nums[1] == 10)
|| (nums[0] == 20 && nums[1] == 20));
}
``````

Sample Output:

```0
1
0
```

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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C Programming: Tips of the Day

Why doesn't a+++++b work?

printf("%d",a+++++b); is interpreted as (a++)++ + b according to the Maximal Munch Rule!.

++ (postfix) doesn't evaluate to an lvalue but it requires its operand to be an lvalue.

! 6.4/4 says the next preprocessing token is the longest sequence of characters that could constitute a preprocessing token"

Ref : https://bit.ly/3fdldUT