﻿ C Program: Check if an array contains twice 10 or 20

# C Exercises: Check a given array of integers and return true if the array contains 10 or 20 twice

## C-programming basic algorithm: Exercise-43 with Solution

Write a C program to check a given array of integers and return true if the array contains 10 or 20 twice. The length of the array will be 0, 1, or 2.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int nums[], int size);

int main(void){
// Declaration and initialization of variables
int arr_size;
int array1[] = {12, 20};

// Calculating the size of the array
arr_size = sizeof(array1)/sizeof(array1);

// Printing the result of calling 'test' function with the first array
printf("%d", test(array1, arr_size));

int array2[] = {20, 20};
arr_size = sizeof(array2)/sizeof(array2);

// Printing the result of calling 'test' function with the second array
printf("\n%d", test(array2, arr_size));

int array3[] =  {10};
arr_size = sizeof(array3)/sizeof(array3);

// Printing the result of calling 'test' function with the third array
printf("\n%d", test(array3, arr_size));
}

// Definition of the 'test' function
int test(int nums[], int size)
{
// Checking if the size is 2 and if the elements meet specific conditions
return size == 2 &&
((nums == 10 && nums == 10) || (nums == 20 && nums == 20));
}
``````

Sample Output:

```0
1
0
```

Pictorial Presentation: Flowchart: C Programming Code Editor:

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