﻿ C exercises: Check if a given array of integers contains 5 next to a 5 somewhere - w3resource C Exercises: Check if a given array of integers contains 5 next to a 5 somewhere

C-programming basic algorithm: Exercise-54 with Solution

Write a C program to check if a given array of integers contains 5 next to a 5 somewhere.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 5, 6, 9, 10, 17};
arr_size = sizeof(array1)/sizeof(array1);
printf("%d",test(array1, arr_size));
int array2[] = {1, 5, 5, 9, 10, 17};
arr_size = sizeof(array2)/sizeof(array2);
printf("\n%d",test(array2, arr_size));
int array3[] = {1, 5, 5, 9, 10, 17, 5, 5};
arr_size = sizeof(array3)/sizeof(array3);
printf("\n%d",test(array3, arr_size));
}
int test(int nums[], int arr_size)
{
for (int i = 0; i < arr_size - 1; i++)
{
if (nums[i] == 5 && nums[i] == nums[i + 1]) return 1;
}
return 0;
}

Sample Output:

0
1
1

Pictorial Presentation: Flowchart: Solution

Contribute your code and comments through Disqus.

﻿