﻿ C : Add numbers except those that begin with a 5 then a 6

# C Exercises: Compute the sum of the numbers in a given array except those numbers starting with 5 followed by atleast one 6

## C-programming basic algorithm: Exercise-53 with Solution

Write a C program to compute the sum of the numbers in a given array except those numbers starting with 5 followed by atleast one 6. Return 0 if the given array has no integer.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

int main(void){
int array1[] = {1, 5, 6, 9, 10, 17};
int arr_size = sizeof(array1)/sizeof(array1[0]);
printf("Sum of values in the array of integers except those numbers starting with 5 followed by atleast one 6: ");
printf("%d",test(array1, arr_size));
}
int test(int nums[], int arr_size)
{
int sum = 0;
int inSection = 0;
for (int i = 0; i < arr_size; i++)
{
if (nums[i] == 5) inSection = 1;
else if (inSection && nums[i] == 6) inSection = 0;
else if (!inSection) sum += nums[i];
}
return sum;
}
``````

Sample Output:

```Sum of values in the array of integers except those numbers starting with 5 followed by atleast one 6: 37
```

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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## C Programming: Tips of the Day

Why doesn't a+++++b work?

printf("%d",a+++++b); is interpreted as (a++)++ + b according to the Maximal Munch Rule!.

++ (postfix) doesn't evaluate to an lvalue but it requires its operand to be an lvalue.

! 6.4/4 says the next preprocessing token is the longest sequence of characters that could constitute a preprocessing token"

Ref : https://bit.ly/3fdldUT