C Exercises: Check if the number of 3's is greater than the number of 5's

C-programming basic algorithm: Exercise-57 with Solution

Write a C program to check if the number of 3's is greater than the number of 5's.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int nums[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 5, 6, 9, 3, 3};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {1, 5, 5, 5, 10, 17};
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = {1, 3, 3, 5, 5, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));
}

// Definition of the 'test' function
int test(int nums[], int arr_size)
{
    int no_3 = 0, no_5 = 0;

    // Looping through the elements of the array
    for (int i = 0; i < arr_size; i++)
    {
        // Checking if the current element is equal to 3 or 5
        if (nums[i] == 3)
        {
            no_3++; // Incrementing count of 3s
        }
        if (nums[i] == 5)
        {
            no_5++; // Incrementing count of 5s
        }
    }

    // Comparing the counts of 3s and 5s, and returning the result
    return no_3 > no_5;
}

Sample Output:

1
0
0

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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