﻿ C Program: Check if an array contains no 3 or 5

# C Exercises: Check if a given array of integers contains no 3 or a 5

## C-programming basic algorithm: Exercise-59 with Solution

Write a C program to check if a given array of integers contains no 3 or 5.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int nums[], int arr_size);

int main(void){
int arr_size;

// Declaration and initialization of an integer array 'array1'
int array1[] = {1, 5, 5, 5, 5};
arr_size = sizeof(array1)/sizeof(array1[0]);

// Printing the result of the 'test' function for 'array1'
printf("%d",test(array1, arr_size));

// Declaration and initialization of an integer array 'array2'
int array2[] = {3, 3, 3, 3 };
arr_size = sizeof(array2)/sizeof(array2[0]);

// Printing the result of the 'test' function for 'array2'
printf("\n%d",test(array2, arr_size));

// Declaration and initialization of an integer array 'array3'
int array3[] = {3, 3, 3, 5, 5, 5};
arr_size = sizeof(array3)/sizeof(array3[0]);

// Printing the result of the 'test' function for 'array3'
printf("\n%d",test(array3, arr_size));

// Declaration and initialization of an integer array 'array4'
int array4[] = {1, 6, 8, 10};
arr_size = sizeof(array4)/sizeof(array4[0]);

// Printing the result of the 'test' function for 'array4'
printf("\n%d",test(array4, arr_size));
}

// Definition of the 'test' function
int test(int nums[], int arr_size)
{
int three = 0, five = 0;

// Looping through the elements of the array
for (int i = 0; i < arr_size; i++)
{
// Checking if the current element is 3
if (nums[i] == 3)
{
three++;
}

// Checking if the current element is 5
if (nums[i] == 5)
{
five++;
}

// If both 3 and 5 are found, return 0 (false)
if (three && five)
{
return 0;
}
}

return 1; // If no instance of both 3 and 5, return 1 (true)
}
``````

Sample Output:

```1
1
0
1
```

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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