﻿ C exercises: Check if a given array of integers contains no 3 or a 5 - w3resource # C Exercises: Check if a given array of integers contains no 3 or a 5

## C-programming basic algorithm: Exercise-59 with Solution

Write a C program to check if a given array of integers contains no 3 or a 5.

C Code:

``````#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 5, 5, 5, 5};
arr_size = sizeof(array1)/sizeof(array1);
printf("%d",test(array1, arr_size));
int array2[] = {3, 3, 3, 3 };
arr_size = sizeof(array2)/sizeof(array2);
printf("\n%d",test(array2, arr_size));
int array3[] = {3, 3, 3, 5, 5, 5};
arr_size = sizeof(array3)/sizeof(array3);
printf("\n%d",test(array3, arr_size));
int array4[] = {1, 6, 8, 10};
arr_size = sizeof(array3)/sizeof(array4);
printf("\n%d",test(array4, arr_size));
}
int test(int nums[], int arr_size)
{
int three = 0, five = 0;
for (int i = 0; i < arr_size; i++)
{
if (nums[i] == 3) three++;
if (nums[i] == 5) five++;
if (three && five) return 0;
}
return 1;
}
``````

Sample Output:

```1
1
0
1
```

Pictorial Presentation: Flowchart: C Programming Code Editor: