﻿ C exercises: Check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both - w3resource C Exercises: Check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both

C-programming basic algorithm: Exercise-60 with Solution

Write a C program to check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 5, 5, 5, 5};
arr_size = sizeof(array1)/sizeof(array1);
printf("%d",test(array1, arr_size));
int array2[] = { 2, 7, 8, 10};
arr_size = sizeof(array2)/sizeof(array2);
printf("\n%d",test(array2, arr_size));
int array3[] = {3, 3, 3, 5, 5, 5};
arr_size = sizeof(array3)/sizeof(array3);
printf("\n%d",test(array3, arr_size));
}

int test(int numbers[], int arr_size)
{
int t_num = 0, f_num = 0;
for (int i = 0; i < arr_size - 1; i++)
{
if (numbers[i] == 3 && numbers[i + 1] == 3)
t_num = 1;
else t_num=0;
if (numbers[i] == 5 && numbers[i + 1] == 5)
f_num = 1;
else f_num=0;
}
return t_num ^ f_num;
}

Sample Output:

1
0
1

Pictorial Presentation: Flowchart: Solution

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