C Exercises: Check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other

C-programming basic algorithm: Exercise-63 with Solution

Write a C program to check a given array of integers. The program will return true if the given array contains either 2 even or 2 odd values all next to each other.

C Code:

#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int numbers[], int arr_size);

int main(void){
    int arr_size;

    // Declaration and initialization of an integer array 'array1'
    int array1[] = {1, 2, 3, 4};
    arr_size = sizeof(array1)/sizeof(array1[0]);

    // Printing the result of the 'test' function for 'array1'
    printf("%d",test(array1, arr_size));

    // Declaration and initialization of an integer array 'array2'
    int array2[] = {3, 3, 5, 5, 5, 5};
    arr_size = sizeof(array2)/sizeof(array2[0]);

    // Printing the result of the 'test' function for 'array2'
    printf("\n%d",test(array2, arr_size));

    // Declaration and initialization of an integer array 'array3'
    int array3[] = {2, 5, 5, 7, 8, 10};
    arr_size = sizeof(array3)/sizeof(array3[0]);

    // Printing the result of the 'test' function for 'array3'
    printf("\n%d",test(array3, arr_size));
}

// Definition of the 'test' function
int test(int numbers[], int arr_size)
{
    int tot_odd = 0, tot_even = 0;

    // Looping through the elements of the array
    for (int i = 0; i < arr_size; i++)
    {
        if (tot_odd < 2 && tot_even < 2)
        {
            if (numbers[i] % 2 == 0)
            {
                tot_even++;
                tot_odd = 0;
            }
            else
            {
                tot_odd++;
                tot_even = 0;
            }
        }
    }

    // Returning true if there are exactly 2 consecutive even or odd numbers
    return tot_odd == 2 || tot_even == 2;
}

Sample Output:

0
1
1

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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