﻿ C : 5 appears 5 times in an array and no 5 is adjacent

# C Exercises: Check a given array of integers and return true if the value 5 appears 5 times and there are no 5 next to each other

## C-programming basic algorithm: Exercise-64 with Solution

Write a C program to check a given array of integers. The program will return true if the value 5 appears 5 times and there are no 5 next to each other.

C Code:

``````#include <stdio.h>
#include <stdlib.h>

// Function prototype for 'test'
int test(int numbers[], int arr_size);

int main(void){
int arr_size;

// Declaration and initialization of an integer array 'array1'
int array1[] = { 3, 5, 1, 5, 3, 5, 7, 5, 1, 5 };
arr_size = sizeof(array1)/sizeof(array1);

// Printing the result of the 'test' function for 'array1'
printf("%d",test(array1, arr_size));

// Declaration and initialization of an integer array 'array2'
int array2[] = {3, 5, 5, 5, 5, 5, 5};
arr_size = sizeof(array2)/sizeof(array2);

// Printing the result of the 'test' function for 'array2'
printf("\n%d",test(array2, arr_size));

// Declaration and initialization of an integer array 'array3'
int array3[] = {3, 5, 2, 5, 4, 5, 7, 5, 8, 5};
arr_size = sizeof(array3)/sizeof(array3);

// Printing the result of the 'test' function for 'array3'
printf("\n%d",test(array3, arr_size));

// Declaration and initialization of an integer array 'array4'
int array4[] = {2, 4, 5, 5, 5, 5};
arr_size = sizeof(array4)/sizeof(array4);

// Printing the result of the 'test' function for 'array4'
printf("\n%d",test(array4, arr_size));
}

// Definition of the 'test' function
int test(int numbers[], int arr_size)
{
int flag = 0;
int five = 0;

// Looping through the elements of the array
for (int i = 0; i < arr_size; i++)
{
if (numbers[i] == 5 && !flag)
{
five++;
flag = 1;
}
else
{
flag = 0;
}
}

// Returning true if there are exactly 5 consecutive occurrences of the number 5
return five == 5;
}
``````

Sample Output:

```1
0
1
0
```

Pictorial Presentation: Flowchart: C Programming Code Editor:

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