C Exercises: Accept an integer and print next ten consecutive odd and even numbers

C Basic Declarations and Expressions: Exercise-107 with Solution

Print next 10 odd and even numbers after a given integer

Write a C program that prints ten consecutive odd and even numbers after accepting an integer.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
  int a, i, ctr = 0;
  
  // Prompt the user to input an integer number
  printf("Input an integer number:\n");
  scanf("%d", &a);

  // Print the next 10 consecutive odd numbers
  printf("\nNext 10 consecutive odd numbers:\n");
  
  for (i = a + 1; ctr < 10; i++){

    if (i % 2 != 0){

      printf("%d, ", i);
      ctr++;
      
    }
  }
  
  // Reset counter for even numbers
  ctr = 0;
  
  // Print the next 10 consecutive even numbers
  printf("\n\nNext 10 consecutive even numbers:\n");
  
  for (i = a + 1; ctr < 10; i++){

    if (i % 2 == 0){

      printf("%d, ", i);
      ctr++;
      
    }
  }
}

Sample Output:

Input an integer number:
15

Next 10 consecutive odd numbers:
17, 19, 21, 23, 25, 27, 29, 31, 33, 35,

Next 10 consecutive even numbers:
26, 28, 30, 32, 34, 36, 38, 40, 42, 44,

Flowchart:

C programming Code Editor:

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