C Exercises: Accept 7 integer values and count the even, odd, positive and negative values

C Basic Declarations and Expressions: Exercise-106 with Solution

Count even, odd, positive, and negative values from 7 integers

Write a C program that accepts 7 integer values and counts the even, odd, positive and negative values.

Sample Solution:

C Code:

#include <stdio.h>

int main () 
{
    // Declare variables for input, counters for even, odd, positive, and negative numbers
    int x, i, ctr_even = 0, ctr_odd = 0, ctr_positive = 0, ctr_negative = 0;

    // Prompt the user to input 7 integers
    printf("\nInput 7 integers:\n");

    // Loop through 7 times to read the numbers
    for (i = 0; i < 7; i++){

        // Read an integer
        scanf("%d", &x);

        // Check if the number is positive
        if (x > 0){
            ctr_positive++;  // Increment positive counter
        }

        // Check if the number is negative
        if (x < 0){
            ctr_negative++;  // Increment negative counter
        }

        // Check if the number is even
        if (x % 2 == 0){
            ctr_even++;  // Increment even counter
        }

        // Check if the number is odd
        if (x % 2 != 0){
            ctr_odd++;  // Increment odd counter
        }
    }

    // Print the counts of even, odd, positive, and negative numbers
    printf("\nNumber of even values: %d", ctr_even);
    printf("\nNumber of odd values: %d", ctr_odd);
    printf("\nNumber of positive values: %d", ctr_positive);
    printf("\nNumber of negative values: %d", ctr_negative);
}

Sample Output:

Input 7 integers:
10
12
15
-15
26
35
17

Number of even values: 3
Number of odd values: 4
Number of positive values: 6
Number of negative values: 1

Flowchart:

C programming Code Editor:

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