C Exercises: Array fill, replace each subsequent position of the array by one-third value of the previous

C Basic Declarations and Expressions: Exercise-129 with Solution

Write a C program that reads an array (length 10), and replaces the first element of the array by a given number and replaces each subsequent position of the array by one-third the value of the previous.

Sample Solution:

C Code:

#include <stdio.h>
int main ()
{
  int i;
  double array_nums[10];
  double n;

  // Prompt user for input
  printf("Input a number:\n");
  scanf("%lf", &n);

  // Initialize the first element of the array with the input value
  array_nums[0] = n;

  // Loop to generate and store subsequent array elements
  for (i = 1; i < 10; i++)
  {
    n = n / 3;  // Divide the current value by 3
    array_nums[i] = n; // Store the result in the array
  }

  // Print the array elements
  printf("\nArray elements:\n");
  for (i = 0; i < 10; i++)
  {
    printf("array_nums[%d] = %.4lf\n", i, array_nums[i]);
  }

  return 0; // End of program
}

Sample Output:

Input a number:
35

Array elements:
array_nums[0] = 35.0000
array_nums[1] = 11.6667
array_nums[2] = 3.8889
array_nums[3] = 1.2963
array_nums[4] = 0.4321
array_nums[5] = 0.1440
array_nums[6] = 0.0480
array_nums[7] = 0.0160
array_nums[8] = 0.0053
array_nums[9] = 0.0018

Flowchart:

C programming Code Editor:

Previous: Write a C program that reads an array of integers (length 10), fill the array elements with number o to a (given number) n – 1 repeated times where 2 <= n <= 10.
Next: Write a C program to create an array of length n and fill the array elements with integer values. Now find the smallest value and it’s position within the array.