C Exercises: Fill the array elements with number o to n – 1 repeated times
C Basic Declarations and Expressions: Exercise-128 with Solution
Write a C program that reads an array of integers (length 10), fills it with numbers from o to a (given number) n – 1 repeatedly, where 2 ≤ n ≤ 10.
Sample Solution:
C Code:
#include <stdio.h>
int main ()
{
int n, i, array_nums[10], k;
// Prompt user for input
printf("Input an integer (2-10)\n");
scanf("%d", &n);
if (n >= 2 && n <= 10)
{
k = 0;
// Loop to fill array with sequential numbers, starting from 0
for (i = 0; i < 10; i++)
{
array_nums[i] = k;
k++;
if (k == n)
{
k = 0;
}
}
// Loop to print array elements
for (i = 0; i < 10; i++)
{
printf("array_nums[%d] = %d\n", i, array_nums[i]);
}
}
return 0; // End of program
}
Sample Output:
Input an integer (2-10) 8 array_nums[0] = 0 array_nums[1] = 1 array_nums[2] = 2 array_nums[3] = 3 array_nums[4] = 4 array_nums[5] = 5 array_nums[6] = 6 array_nums[7] = 7 array_nums[8] = 0 array_nums[9] = 1
Flowchart:
C programming Code Editor:
Previous: Write a C program that reads an array of integers (length 8), replace the 1st element by the 8th, 2nd by the 7th and so on. Print the final array.
Next: Write a C program that reads an array (length 10), and replace the first element of the array by a give number and replace each subsequent position of the array by one-third value of the previous.
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