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C Exercises: Check whether a character is an alphabet, digit or special character

C Conditional Statement: Exercise-16 with Solution

Write a C program to check whether a character is an alphabet, digit or special character.

Pictorial Presentation:

Check whether a character is an alphabet, digit or special character

Sample Solution:

C Code:

#include <stdio.h>
int main()  
{  
    char sing_ch;  

    printf("Input a character: ");  
    scanf('%c', &sing_ch);  
  
    /* Checks whether it is an alphabet */  
    if((sing_ch>='a' && sing_ch<='z') || (sing_ch>='A' && sing_ch<='Z'))  
    {  
        printf("This is an alphabet.\n");  
    }  
    else if(sing_ch>='0' && sing_ch<='9') /* whether it is digit */  
    {  
        printf("This is a digit.\n");  
    }  
    else /* Else special character */  
    {  
        printf("This is a special character.\n");  
    }  
}

Sample Output:

Input a character: @                                                                                          
This is a special character.

Flowchart:

Flowchart: Check whether a character is alphabet, digit or special character

C Programming Code Editor:

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Next: Write a C program to check whether an alphabet is a vowel or consonant.

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C Programming: Tips of the Day

Why do C and C++ compilers allow array lengths in function signatures when they're never enforced?

It is a quirk of the syntax for passing arrays to functions.

Actually it is not possible to pass an array in C. If you write syntax that looks like it should pass the array, what actually happens is that a pointer to the first element of the array is passed instead.

Since the pointer does not include any length information, the contents of your [] in the function formal parameter list are actually ignored.

Ref : https://bit.ly/3fhlvdH