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C Exercises: Check whether an alphabet is a vowel or consonant

C Conditional Statement: Exercise-17 with Solution

Write a C program to check whether an alphabet is a vowel or consonant.

Pictorial Presentation:

Check whether an alphabet is a vowel or consonant

Sample Solution:

C Code:

#include <stdio.h>
void main()  
{  
    char sing_ch;  
    
    printf("Input any alphabet : ");  
    scanf("%c", &sing_ch);  
  
    if(sing_ch=='a' || sing_ch=='e' || sing_ch=='i' || sing_ch=='o' || sing_ch=='u' || sing_ch=='A' || sing_ch=='E' || sing_ch=='I' || sing_ch=='O' 

|| sing_ch=='U')  
    {  
        printf("The alphabet is a vowel.\n");  
    }  
    else if((sing_ch>='a' && sing_ch<='z') || (sing_ch>='A' && sing_ch<='Z'))  
    {  
        printf("The alphabet is a consonant.\n");  
    }  
    else  
    {  
        printf("The character is not an alphabet.\n");  
    }   
}
 

Sample Output:

Input any alphabet : K                                                                                        
The alphabet is a consonant. 

Flowchart:

Flowchart: Check whether an alphabet is vowel or consonant

C Programming Code Editor:

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C Programming: Tips of the Day

Why do C and C++ compilers allow array lengths in function signatures when they're never enforced?

It is a quirk of the syntax for passing arrays to functions.

Actually it is not possible to pass an array in C. If you write syntax that looks like it should pass the array, what actually happens is that a pointer to the first element of the array is passed instead.

Since the pointer does not include any length information, the contents of your [] in the function formal parameter list are actually ignored.

Ref : https://bit.ly/3fhlvdH