C Exercises: Display the pattern like right angle triangle which repeat a number in a row
C For Loop: Exercise-11 with Solution
Write a program in C to make such a pattern like right angle triangle with a number which will repeat a number in a row.
The pattern is as follows:
1 22 333 4444
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int i,j,rows;
printf("Input number of rows : ");
scanf("%d",&rows);
for(i=1;i<=rows;i++)
{
for(j=1;j<=i;j++)
printf("%d",i);
printf("\n");
}
}
Sample Output:
Input number of rows : 10 1 22 333 4444 55555 666666 7777777 88888888 999999999 10101010101010101010
Flowchart:

C Programming Code Editor:
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C Programming: Tips of the Day
Printing hexadecimal characters in C:
You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.
Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.
char int c0 -> ffffffc0 80 -> ffffff80 61 -> 00000061Here's a solution:
char ch = 0xC0; printf("%x", ch & 0xff);
This will mask out the upper bits and keep only the lower 8 bits that you want.
Ref : https://bit.ly/3vOLizM
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