C Exercises: Display the pattern like right angle triangle which repeat a number in a row

C For Loop: Exercise-11 with Solution

Write a program in C to make such a pattern like a right angle triangle with a number which will repeat a number in a row.
The pattern is as follows:

 1
 22
 333
 4444

This C program creates a right-angle triangle pattern where each row displays a repetition of the row number. The pattern starts with a single digit in the first row and increases with each subsequent row. The program utilizes nested "for" loops to control the number of rows and repetitions of each digit, producing the desired pattern.

Visual Presentation:

Sample Solution:

C Code:

#include <stdio.h>  // Include the standard input/output header file.

void main() {
    int i, j, rows;  // Declare variables 'i' and 'j' for loop counters, 'rows' for user input.

    printf("Input number of rows : ");  // Print a message to prompt user input.
    scanf("%d", &rows);  // Read the value of 'rows' from the user.

    for (i = 1; i <= rows; i++) {  // Start a loop to generate rows.
        for (j = 1; j <= i; j++)  // Nested loop to print numbers based on the current row.
            printf("%d", i);  // Print the value of 'i'.

        printf("\n");  // Move to the next line for the next row.
    }
}

Output:

Input number of rows : 10                                                                                     
1                                                                                                             
22                                                                                                            
333                                                                                                           
4444                                                                                                          
55555                                                                                                         
666666                                                                                                        
7777777                                                                                                       
88888888                                                                                                      
999999999                                                                                                     
10101010101010101010 

Explanation:

for (i = 1; i <= rows; i++) {
  for (j = 1; j <= i; j++)
    printf("%d", i);
  printf("\n");
}

In the said for loop, the variable i is initialized to 1, and the loop will continue as long as i is less than or equal to the value of variable 'rows'. In each iteration of the outer loop, another loop is started with variable j, initialized to 1, and it will continue as long as j is less than or equal to the value of i.

In each iteration of the inner loop, the printf() function will print the value of j to the console. This value will be printed j times, as the value of j is increasing by 1 in each iteration of the inner loop.

After the inner loop completes, the outer loop will print a newline character (\n) to create a new line.

The outer loop will increment the value of i by 1, and the process will repeat until the condition i<=rows is no longer true.

Flowchart:

C Programming Code Editor:

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