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C Exercises: Display the pattern like a pyramid with a number which will repeat the number in the same row

C For Loop: Exercise-17 with Solution

Write a program in C to make such a pattern like a pyramid with a number which will repeat the number in the same row.
The pattern is as follows:

   1
  2 2
 3 3 3
4 4 4 4

Pictorial Presentation:

Display the pattern like a pyramid with a number which will repeat the number in the same row

Sample Solution:

C Code:

#include <stdio.h>

void main()
{
   int i,j,spc,rows,k;
   printf("Input number of rows : ");
   scanf("%d",&rows);
   spc=rows+4-1;
   for(i=1;i<=rows;i++)
   {
         for(k=spc;k>=1;k--)
            {
              printf(" ");
            }
                      
	   for(j=1;j<=i;j++)
	   printf("%d ",i);
	printf("\n");
    spc--;
   }
}

Sample Output:

Input number of rows : 5                                                                                      
        1                                                                                                     
       2 2                                                                                                    
      3 3 3                                                                                                   
     4 4 4 4                                                                                                  
    5 5 5 5 5

Flowchart:

Flowchart: Display the pattern like pyramid with number which will repeat the number in a same row

C Programming Code Editor:

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Previous: Write a program in C to display the n terms of even natural number and their sum.
Next: Write a program in C to find the sum of the series [ 1-X^2/2!+X^4/4!- .........].

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution:
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM