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C Exercises: Calculate n terms of even natural number and their sum

C For Loop: Exercise-16 with Solution

Write a program in C to display the n terms of even natural number and their sum.

Pictorial Presentation:

Calculate n terms of even natural number and their sum

Sample Solution:

C Code:

#include <stdio.h>

void main()
{
   int i,n,sum=0;

   printf("Input number of terms : ");
   scanf("%d",&n);
   printf("\nThe even numbers are :");
   for(i=1;i<=n;i++)
   {
     printf("%d ",2*i);
     sum+=2*i;
   }
   printf("\nThe Sum of even Natural Number upto %d terms : %d \n",n,sum);
} 

Sample Output:

Input number of terms : 5                                                                                     
                                                                                                              
The even numbers are :2 4 6 8 10                                                                              
The Sum of even Natural Number upto 5 terms : 30 

Flowchart:

Flowchart: Calculate n terms of even natural number and their sum

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Next: Write a program in C to make such a pattern like a pyramid with a number which will repeat the number in the same row.

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution:
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM