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C Exercises: Calculate the harmonic series and their sum

C For Loop: Exercise-19 with Solution

Write a program in C to display the n terms of harmonic series and their sum. The series is :
1 + 1/2 + 1/3 + 1/4 + 1/5 ... 1/n terms

Pictorial Presentation:

Calculate the harmonic series and their sum

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
   int i,n;
   float s=0.0;
   printf("Input the number of terms : ");
   scanf("%d",&n);
   printf("\n\n");
   for(i=1;i<=n;i++)
   {
       if(i<n)
       {
     printf("1/%d + ",i);
     s+=1/(float)i;
       }
     if(i==n)
     {
     printf("1/%d ",i);
     s+=1/(float)i;
     }
     }
        printf("\nSum of Series upto %d terms : %f \n",n,s);
}  

Sample Output:

Input the number of terms : 5                                                                                 
                                                                                                                                                                                        
1/1 + 1/2 + 1/3 + 1/4 + 1/5                                                                                   
Sum of Series upto 5 terms : 2.283334  

Flowchart:

Flowchart: Calculate the harmonic series and their sum

C Programming Code Editor:

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Previous: Write a program in C to find the sum of the series [ 1-X^2/2!+X^4/4!- .........].
Next: Write a program in C to display the pattern like a pyramid using asterisk and each row contain an odd number of asterisks.

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution:
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM