C Exercises: Display the pattern like a diamond
C For Loop: Exercise-31 with Solution
Write a program in C to display the pattern like a diamond. The pattern is as follows :
* *** ***** ******* ********* ******* ***** *** *
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int i,j,r;
printf("Input number of rows (half of the diamond) :");
scanf("%d",&r);
for(i=0;i<=r;i++)
{
for(j=1;j<=r-i;j++)
printf(" ");
for(j=1;j<=2*i-1;j++)
printf("*");
printf("\n");
}
for(i=r-1;i>=1;i--)
{
for(j=1;j<=r-i;j++)
printf(" ");
for(j=1;j<=2*i-1;j++)
printf("*");
printf("\n");
}
}
Sample Output:
Input number of rows (half of the diamond) :5 * *** ***** ******* ********* ******* ***** *** *
Flowchart:

C Programming Code Editor:
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C Programming: Tips of the Day
Is there a way to specify how many characters of a string to print out using printf()?
The basic way is:
printf ("Here are the first 8 chars: %.8s\n", "A string that is more than 8 chars");
The other, often more useful, way is:
printf ("Here are the first %d chars: %.*s\n", 8, 8, "A string that is more than 8 chars");
Here, you specify the length as an int argument to printf(), which treats the '*' in the format as a request to get the length from an argument.
You can also use the notation:
printf ("Here are the first 8 chars: %*.*s\n", 8, 8, "A string that is more than 8 chars");
This is also analogous to the "%8.8s" notation, but again allows you to specify the minimum and maximum lengths at runtime - more realistically in a scenario like:
printf("Data: %*.*s Other info: %d\n", minlen, maxlen, string, info);
The POSIX specification for printf() defines these mechanism
Ref : https://bit.ly/3u32GyO
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