C Exercises: Find the Armstrong number for a given range of number
C For Loop: Exercise-30 with Solution
Write a C program to find the Armstrong number for a given range of number.
Sample Solution:
C Code:
/*When the sum of the cube of the individual digits of a number
is equal to that number, the number is called Armstrong number. For example 153.
Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/
#include <stdio.h>
void main(){
int num,r,sum,temp;
int stno,enno;
printf("Input starting number of range: ");
scanf("%d",&stno);
printf("Input ending number of range : ");
scanf("%d",&enno);
printf("Armstrong numbers in given range are: ");
for(num=stno;num<=enno;num++){
temp=num;
sum = 0;
while(temp!=0){
r=temp % 10;
temp=temp/10;
sum=sum+(r*r*r);
}
if(sum==num)
printf("%d ",num);
}
printf("\n");
}
Sample Output:
Input starting number of range: 1 Input ending number of range : 1000 Armstrong numbers in given range are: 1 153 370 371 407
Flowchart:

C Programming Code Editor:
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Previous: Write a C program to check whether a given number is an armstrong number or not.
Next: Write a program in C to display the pattern like a diamond.
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C Programming: Tips of the Day
C Programming - What is the difference between char s[] and char *s?
The difference here is that
char *s = "Hello world";
will place "Hello world" in the read-only parts of the memory, and making s a pointer to that makes any writing operation on this memory illegal.
While doing:
char s[] = "Hello world";
puts the literal string in read-only memory and copies the string to newly allocated memory on the stack. Thus making legal.
s[0] = 'J';
Ref : https://bit.ly/2NDbgoX
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