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C Exercises: Check whether a given number is an armstrong number or not

C For Loop: Exercise-29 with Solution

Write a C program to check whether a given number is an armstrong number or not.

When the sum of the cube of the individual digits of a number is equal to that number, the number is called Armstrong number. For Example 153 is an Armstrong number because 153 = 13+53+33.

Test Data :
Input a number: 153
Expected Output :
153 is an Armstrong number.

Pictorial Presentation:

Check whether a given number is an armstrong number or not

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Sample Solution:

C Code:

#include <stdio.h>

void main(){
    int num,r,sum=0,temp;

    printf("Input  a number: ");
    scanf("%d",&num);

    for(temp=num;num!=0;num=num/10){
         r=num % 10;
         sum=sum+(r*r*r);
    }
    if(sum==temp)
         printf("%d is an Armstrong number.\n",temp);
    else
         printf("%d is not an Armstrong number.\n",temp);

}

Sample Output:

Input  a number: 153                                                                                          
153 is an Armstrong number.   

Flowchart:

Flowchart : Find perfect numbers within a given number of range

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Previous: Write a c program to find the perfect numbers within a given number of range.
Next: Write a C program to find the Armstrong number for a given range of number.

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C Programming: Tips of the Day

What is the size of an enum in c?

An enum is only guaranteed to be large enough to hold int values. The compiler is free to choose the actual type used based on the enumeration constants defined so it can choose a smaller type if it can represent the values you define. If you need enumeration constants that don't fit into an int you will need to use compiler-specific extensions to do so.

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