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C Exercises: Print a string in reverse order

C For Loop: Exercise-57 with Solution

Write a program in C to print a string in reverse order.

Pictorial Presentation:

Print a string in reverse order

Sample Solution:

C Code:

#include <stdio.h>
#include <string.h>
 
void main()
{
   char str1[100], tmp;
   int l, lind, rind,i;

       printf("\n\nPrint a string in reverse order:\n ");
       printf("-------------------------------------\n");

   printf("Input a string to reverse : ");
   scanf("%s", str1);
   l = strlen(str1);

   lind = 0;
   rind = l-1;
    
for(i=lind;i<rind;i++)
       {
       tmp = str1[i];
       str1[i] = str1[rind];
       str1[rind] = tmp;
       rind--;
   }
 
   printf("Reversed string is: %s\n\n", str1);
}

Sample Output: 

Print a string in reverse order:                                                                              
 -------------------------------------                                                                        
Input a string to reverse : Welcome                                                                           
Reversed string is: emocleW

Flowchart:

Flowchart : Print a string in reverse order

C Programming Code Editor:

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Next: Write a C program to find the length of a string without using the library function.

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution: 
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM