C Exercises: Print a string in reverse order
C For Loop: Exercise-57 with Solution
Write a program in C to print a string in reverse order.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
void main()
{
char str1[100], tmp;
int l, lind, rind,i;
printf("\n\nPrint a string in reverse order:\n ");
printf("-------------------------------------\n");
printf("Input a string to reverse : ");
scanf("%s", str1);
l = strlen(str1);
lind = 0;
rind = l-1;
for(i=lind;i<rind;i++)
{
tmp = str1[i];
str1[i] = str1[rind];
str1[rind] = tmp;
rind--;
}
printf("Reversed string is: %s\n\n", str1);
}
Sample Output:
Print a string in reverse order: ------------------------------------- Input a string to reverse : Welcome Reversed string is: emocleW
Flowchart:

C Programming Code Editor:
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Previous: Write a program in C to Check Whether a Number can be Express as Sum of Two Prime Numbers.
Next: Write a C program to find the length of a string without using the library function.
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C Programming: Tips of the Day
Printing hexadecimal characters in C:
You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.
Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.
char int c0 -> ffffffc0 80 -> ffffff80 61 -> 00000061Here's a solution:
char ch = 0xC0; printf("%x", ch & 0xff);
This will mask out the upper bits and keep only the lower 8 bits that you want.
Ref : https://bit.ly/3vOLizM
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