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C Exercises: Compute multiplication table of a given integer

C For Loop: Exercise-6 with Solution

Write a program in C to display the multiplication table of a given integer.

Pictorial Presentation:

Compute multiplication table of a given integer

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
   int j,n;
   printf("Input the number (Table to be calculated) : ");
   scanf("%d",&n);
   printf("\n");
   for(j=1;j<=10;j++)
   {
     printf("%d X %d = %d \n",n,j,n*j);
   }
} 

Sample Output:

Input the number (Table to be calculated) : 15                                                                
                                                                                                              
15 X 1 = 15                                                                                                   
15 X 2 = 30                                                                                                   
15 X 3 = 45                                                                                                   
15 X 4 = 60                                                                                                   
15 X 5 = 75                                                                                                   
15 X 6 = 90                                                                                                   
15 X 7 = 105                                                                                                  
15 X 8 = 120                                                                                                  
15 X 9 = 135                                                                                                  
15 X 10 = 150

Flowchart:

Flowchart: Compute multiplication table of a given integer

C Programming Code Editor:

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Previous: Write a program in C to display the cube of the number upto a given integer.
Next: Write a program in C to display the multiplication table vertically from 1 to n.

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C Programming: Tips of the Day

Printing hexadecimal characters in C:

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
Here's a solution:
char ch = 0xC0;
printf("%x", ch & 0xff);

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM