w3resource

C Exercises: Check if a given integer is a power of three

C Programming Mathematics: Exercise-13 with Solution

Write a C program to check if a given integer is a power of three.

Example:
Input: 9
Output: true
Input: 81
Output: true
Input: 45
Output: false

Visual Presentation:

C Exercises: Check if a given integer is a power of threen

Sample Solution:

C Code:

#include <stdio.h>
#include <stdbool.h>

// Function to check if a number is a power of three
static bool is_PowerOf_Three(int n) {
#if 0 // Alternative approach using recursive function
    if (n == 1) return true; // Base case: If n is 1, it is a power of three
    if (n == 0 || n % 3) return false; // If n is not divisible by 3 or is 0, it is not a power of three
    return is_PowerOf_Three(n / 3); // Recursively check if n divided by 3 is a power of three
#else // Optimized approach using mathematical property
    return (n > 0 && (1162261467 % n) == 0); // Return true if n is greater than 0 and 1162261467 is divisible by n
#endif
}

// Main function to test the is_PowerOf_Three function with different numbers
int main(void) {
    int n = 9;
    printf("\nIf %d is a power of three? %d", n, is_PowerOf_Three(n));
    n = 81;
    printf("\n\nIf %d is a power of three? %d", n, is_PowerOf_Three(n));
    n = 45;
    printf("\n\nIf %d is a power of three? %d", n, is_PowerOf_Three(n));
    return 0;
}

Sample Output:

If 9 is power of three? 1

If 81 is power of three? 1

If 45 is power of three? 0

Flowchart:

Flowchart: Check if a given integer is a power of three.

C Programming Code Editor:

Improve this sample solution and post your code through Disqus.

Previous: Write a C programming to add repeatedly all digits of a given non-negative number until the result has only one digit.
Next: Write a C programming to calculate the number of 1's in their binary representation and return them as an array.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.