﻿ C - Count common factors of two integers

# C Programming: Count common factors of two integers

## C Programming Mathematics: Exercise-36 with Solution

Write a C program to count common factors of the two given integers.

Factor - A number or algebraic expression that divides another evenly, that is, without leaving a remainder.

Example:
Input: m = 18, b = 6
Factors of 18 are 1, 2, 3, 6, 9, 18
Factors of 18 are 1, 2, 3, 6
Common factors of the said two numbers are - 1,2,3,6
Output: 4

Test Data:
(18, 6) -> 4
(45, 105) -> 4

Sample Solution:

C Code:

``````#include <stdio.h>
#include <math.h>

// Function to find the number of common factors between two integers x and y
int test(int x, int y) {
int z, count = 0;

// Find the smallest number among x and y and assign it to integer z
if (x > y) {
z = y;
} else {
z = x;
}

// Count the common factors of two numbers
for (int i = 1; i <= z; i++) {
if (x % i == 0 && y % i == 0) {
count++; // Increment the count if 'i' is a common factor of both x and y
}
}

return count; // Return the count of common factors
}

// Main function
int main(void) {
int m = 18;
int n = 6;
printf("m = %d, n = %d", m, n);
printf("\nCommon factors of the said two numbers = %d", test(m, n));

// Testing with different values
m = 45;
n = 105;
printf("\nm = %d, n = %d", m, n);
printf("\nCommon factors of the said two numbers = %d", test(m, n));
}
```
```

Sample Output:

```m = 18, n = 6
Common factors of the said two numbers = 4
m = 45, n = 105
Common factors of the said two numbers = 4
```

Flowchart:

C Programming Code Editor:

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