C Exercises: Check whether a given number is Abundant or not
C Numbers: Exercise-2 with Solution
Write a program in C to check whether a given number is Abundant or not.
Test Data
Input an integer number: 18
Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include <math.h>
// Function to calculate the sum of divisors of a number
int getSum(int n)
{
int sum = 0;
for (int i = 1; i <= sqrt(n); i++) // Loop through numbers from 1 to the square root of 'n'
{
if (n % i == 0) // Check if 'i' is a divisor of 'n'
{
if (n / i == i)
sum = sum + i; // If 'i' is a divisor and is equal to the square root of 'n', add it to 'sum'
else
{
sum = sum + i; // Add 'i' to 'sum'
sum = sum + (n / i); // Add 'n / i' to 'sum'
}
}
}
sum = sum - n; // Subtract the number 'n' from the sum of its divisors
return sum; // Return the sum of divisors
}
// Function to check if a number is an abundant number
bool checkAbundant(int n)
{
return getSum(n) > n; // Return true if the sum of divisors is greater than 'n', otherwise return false
}
// Main function
int main()
{
int n;
printf("\n\n Check whether a given number is an Abundant number:\n");
printf(" --------------------------------------------------------\n");
printf(" Input an integer number: ");
scanf("%d", &n); // Read an integer from the user and store it in variable 'n'
// Check if the number is abundant and print the result
checkAbundant(n) ? printf(" The number is Abundant.\n") : printf(" The number is not Abundant.\n");
return 0;
}
Sample Output:
Input an integer number: 18 The number is Abundant.
Visual Presentation:
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