C Exercises: Find the Abundant numbers (integers) between 1 to 1000

C Numbers: Exercise-3 with Solution

Write a program in C to find the Abundant numbers (integers) between 1 to 1000.

Sample Solution:

C Code:

# include <stdio.h>
# include <string.h>
# include <stdbool.h>
# include <math.h>

int getSum(int n)
{
    int sum = 0;
    for (int i=1; i<=sqrt(n); i++)
    {
        if (n%i==0)
        {
            if (n/i == i)
                sum = sum + i;
            else 
            {
                sum = sum + i;
                sum = sum + (n / i);
            }
        }
    }
    sum = sum - n;
    return sum;
}
bool checkAbundant(int n)
{
    return (getSum(n) > n);
}
int main()
{
int n;
  printf("\n\n The Abundant number between 1 to 1000 are: \n");
  printf(" -----------------------------------------------\n");
for(int j=1;j<=1000;j++)
{
    n=j;
if(checkAbundant(n)==true)
printf("%d ",n);

}
 printf("\n");
}

Sample Output:

 The Abundant number between 1 to 1000 are:                                                                 
 -----------------------------------------------                                                              
12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80...  

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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