C Exercises: Check two numbers are Amicable numbers or not
C Numbers: Exercise-25 with Solution
Write a program in C to check whether two numbers are Amicable numbers or not.
Test DataInput the 1st number : 1184
Input the 2nd number : 1210
Sample Solution:
C Code:
# include <stdio.h>
# include <stdlib.h>
# include <stdbool.h>
# include <math.h>
int ProDivSum(int n)
{
int sum = 1;
for (int i=2; i<=sqrt(n); i++)
{
if (n%i == 0)
{
sum += i;
if (n/i != i)
sum += n/i;
}
}
return sum;
}
bool chkAmicable(int a,int b)
{
return(ProDivSum(a) == b && ProDivSum(b) == a);
}
int main()
{
int n, i, j, ctr,nm1,nm2;
printf("\n\n Check whether two numbers are Amicable pairs or not: \n");
printf("\n Sample: (220, 284), (1184, 1210), (2620, 2924).. \n");
printf(" --------------------------------------------------------\n");
printf(" Input the 1st number : ");
scanf("%d",&nm1);
printf(" Input the 2nd number : ");
scanf("%d",&nm2);
if( chkAmicable(nm1,nm2))
printf(" The given numbers are an Amicable pair.\n");
else
printf(" The given numbers are not an Amicable pair.\n");
return 0;
}
Sample Output:
Input the 1st number : 1184 Input the 2nd number : 1210 The given numbers are an Amicable pair.
Pictorial Presentation:
Flowchart:

C Programming Code Editor:
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Next: Write a program in C to count the amicable pairs in an array.
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C Programming: Tips of the Day
Why #define TRUE (1==1) in a C boolean macro instead of simply as 1?
This approach will use the actual boolean type (and resolve to true and false) if the compiler supports it. (specifically, C++)
However, it would be better to check whether C++ is in use (via the __cplusplus macro) and actually use true and false.
In a C compiler, this is equivalent to 0 and 1.
(note that removing the parentheses will break that due to order of operations)
Ref : https://bit.ly/3mbkkAr
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