﻿ C Program: Check two numbers are Amicable numbers or not - w3resource

# C Exercises: Check two numbers are Amicable numbers or not

## C Numbers: Exercise-25 with Solution

Write a program in C to check whether two numbers are Amicable numbers or not.

Test Data
Input the 1st number : 1184
Input the 2nd number : 1210

Sample Solution:

C Code:

``````# include <stdio.h>
# include <stdlib.h>
# include <stdbool.h>
# include <math.h>

// Function to find the sum of proper divisors of a number 'n'
int ProDivSum(int n)
{
int sum = 1;
for (int i = 2; i <= sqrt(n); i++) // Loop to find divisors of 'n'
{
if (n % i == 0)
{
sum += i; // Adding divisor 'i' to the sum
if (n / i != i)
sum += n / i; // Adding the corresponding divisor to the sum
}
}
return sum; // Returning the sum of divisors
}

// Function to check if two numbers 'a' and 'b' are Amicable pairs
bool chkAmicable(int a, int b)
{
return (ProDivSum(a) == b && ProDivSum(b) == a); // Checking if the sums of divisors of 'a' and 'b' match each other
}

// Main function
int main()
{
int nm1, nm2; // Variables to store the input numbers

printf("\n\n Check whether two numbers are Amicable pairs or not: \n");
printf("\n Sample: (220, 284), (1184, 1210), (2620, 2924).. \n");
printf(" --------------------------------------------------------\n");
printf(" Input the 1st number : ");
scanf("%d", &nm1);
printf(" Input the 2nd number : ");
scanf("%d", &nm2);

if (chkAmicable(nm1, nm2)) // Checking if 'nm1' and 'nm2' are Amicable pairs using the function
printf(" The given numbers are an Amicable pair.\n"); // Printing if the numbers are an Amicable pair
else
printf(" The given numbers are not an Amicable pair.\n"); // Printing if the numbers are not an Amicable pair

return 0; // Returning 0 to indicate successful execution
}
```
```

Sample Output:

``` Input the 1st number : 1184
Input the 2nd number : 1210
The given numbers are an Amicable pair.
```

Visual Presentation:

Flowchart:

C Programming Code Editor:

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