C Exercises: How to handle the pointers in the program

C Pointer : Exercise-2 with Solution

Write a program in C to demonstrate how to handle pointers in a program..

Pictorial Presentation:

Sample Solution:

C Code:

#include <stdio.h>
int main()
{
   int* ab;
   int m;
   m=29;
    printf("\n\n Pointer : How to  handle the pointers in the program :\n"); 
    printf("------------------------------------------------------------\n");
    printf(" Here in the declaration ab = int pointer, int m= 29\n\n");
    
   printf(" Address of m : %p\n",&m);
   printf(" Value of m : %d\n\n",m);
   ab=&m;
   printf(" Now ab is assigned with the address of m.\n");
   printf(" Address of pointer ab : %p\n",ab);
   printf(" Content of pointer ab : %d\n\n",*ab);
   m=34;
   printf(" The value of m assigned to 34 now.\n");
   printf(" Address of pointer ab : %p\n",ab);
   printf(" Content of pointer ab : %d\n\n",*ab);
   *ab=7;
   printf(" The pointer variable ab is assigned the value 7 now.\n");
   printf(" Address of m : %p\n",&m);//as ab contain the address of m
                                     //so *ab changed the value of m and now m become 7
   printf(" Value of m : %d\n\n",m);
   return 0;
}

Sample Output:

 Pointer : How to  handle the pointers in the program :                                                       
------------------------------------------------------------                                                  
 Here in the declaration ab = int pointer, int m= 29                                                          
                                                                                                              
 Address of m : 0x7fff24a3f8bc                                                                                
 Value of m : 29                                                                                              
                                                                                                              
 Now ab is assigned with the address of m.                                                                    
 Address of pointer ab : 0x7fff24a3f8bc                                                                       
 Content of pointer ab : 29                                                                                   
                                                                                                              
 The value of m assigned to 34 now.                                                                           
 Address of pointer ab : 0x7fff24a3f8bc                                                                       
 Content of pointer ab : 34                                                                                   
                                                                                                              
 The pointer variable ab is assigned the value 7 now.                                                         
 Address of m : 0x7fff24a3f8bc                                                                                
 Value of m : 7 

Flowchart:

C Programming Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a program in C to show the basic declaration of pointer.
Next: Write a program in C to demonstrate the use of &(address of) and *(value at address) operator.