# C Exercises: Squared sum minus square of 1st 100 numbers

## C Programming Challenges: Exercise-22 with Solution

The sum of the squares of the first ten natural numbers is,

1^{2} + 2^{2} + ... + 10^{2} = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^{2} = 55^{2} = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Write a C program to find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

**C Code:**

```
#include <stdio.h>
int main(void)
{
unsigned sum1 = 0, sum2 = 0, i;
for (i = 1; i <= 100; i++) {
sum1 += i*i;
sum2 += i;
}
printf("%u\n", sum2*sum2 - sum1);
return 0;
}
```

Sample Output:

25164150

**Flowchart:**

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**Previous C Programming Exercise:** Smallest positive number divisible by 1-20.

**Next C Programming Exercise:** Get the 1001st prime number

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