# C Exercises: Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum

## C Programming Practice: Exercise-22 with Solution

The sum of the squares of the first ten natural numbers is,

1^{2} + 2^{2} + ... + 10^{2} = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^{2} = 55^{2} = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Write a C programming to find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

**C Code:**

```
#include <stdio.h>
int main(void)
{
unsigned sum1 = 0, sum2 = 0, i;
for (i = 1; i <= 100; i++) {
sum1 += i*i;
sum2 += i;
}
printf("%u\n", sum2*sum2 - sum1);
return 0;
}
```

Sample Output:

25164150

**Flowchart:**

## C Programming Code Editor:

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**Previous:** Write a C programming to find the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

**Next:** Write a C programming to get the 1001st prime number?

**What is the difficulty level of this exercise?**

## C Programming: Tips of the Day

**The tilde operator in C:**

The ~ operator is bitwise NOT, it inverts the bits in a binary number:

NOT 011100 = 100011

Ref : https://bit.ly/3DR1N24

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