C Exercises: Smallest positive number divisible by 1-20

Last update on March 21 2025 12:36:28 (UTC/GMT +8 hours)

21. Smallest Multiple for 1 to 20 Variants

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
Write a C program to find the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

C Code:

/* Copyright (c) 2009, eagletmt, Released under the MIT License <http://opensource.org/licenses/mit-license.php> */
#include <stdio.h>
static unsigned long gcd(unsigned long a, unsigned long b);
static __inline unsigned long lcm(unsigned long a, unsigned long b);
int main(void)
{
  unsigned long ans = 1;
  unsigned long i;
  for (i = 1; i <= 20; i++) {
    ans = lcm(ans, i);
  }
  printf("%lu\n", ans);
  return 0;
}
unsigned long gcd(unsigned long a, unsigned long b)
{
  unsigned long r;
  if (a > b) {
    unsigned long t = a;
    a = b;
    b = t;
  }
  while (r = a%b) {
    a = b;
    b = r;
  }
  return b;
}
unsigned long lcm(unsigned long a, unsigned long b)
{
  unsigned long long p = (unsigned long long)a * b;
  return p/gcd(a, b);
}

Sample Output:

232792560

Flowchart:

For more Practice: Solve these Related Problems:

Write a C program to find the smallest number divisible by all numbers from 1 to 20 using LCM calculation.
Write a C program to compute the smallest multiple for numbers 1 to n, where n is user-specified.
Write a C program to determine the smallest positive number evenly divisible by numbers 1 to 20 using prime factorization.
Write a C program to calculate the smallest number divisible by a given range of numbers and output the prime factors used.

C Programming Code Editor:

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