C Exercises: Convert a string to a long integer
C Variable Type : Exercise-3 with Solution
Write a C program to convert a string to a long integer.
Sample Solution:
C Code:
#include<stdio.h>
#include<stdlib.h>
int main ()
{
char buffer[] = "2016 40a0b0 -1101110100110111100110 0x5abfff";
char * ptr_end;
long int i1, i2, i3, i4;
i1 = strtol (buffer,&ptr_end,10);
i2 = strtol (ptr_end,&ptr_end,16);
i3 = strtol (ptr_end,&ptr_end,2);
i4 = strtol (ptr_end,NULL,0);
printf ("\nIn decimals: %ld, %ld, %ld, %ld.\n\n", i1, i2, i3, i4);
return 0;
}
Sample Output:
In decimals: 2016, 4235440, -3624422, 5947391.
Flowchart:

C Programming Code Editor:
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Previous: Write a C program to convert a string to an unsigned long integer.
Next: Write a C program to convert a string to a double.
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C Programming: Tips of the Day
How I can print to stderr in C?
The syntax is almost the same as printf. With printf you give the string format and its contents i.e.:
printf("my %s has %d chars\n", "string format", 30);
With fprintf it is the same, except now you are also specifying the place to print to:
File *myFile; ... fprintf( myFile, "my %s has %d chars\n", "string format", 30);
Or in your case:
fprintf( stderr, "my %s has %d chars\n", "string format", 30);
Ref : https://bit.ly/3v5U8Zq
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