C++ Exercises: Check if a given non-negative number is a multiple of 3 or 7, but not both

Last update on April 07 2025 12:56:49 (UTC/GMT +8 hours)

Multiple of 3 or 7 but Not Both

Write a C++ program to check if a given number that is not negative is a multiple of 3 or 7, but not both.

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;

// Function to determine if a number is divisible by 3 or 7 exclusively (but not both)
bool test(int n)
{
    // Returns true if n is divisible by 3 exclusively XOR (n is divisible by 7 exclusively)
    return n % 3 == 0 ^ n % 7 == 0;
}

int main() 
{
    // Testing the test function with different input values
    cout << test(3) << endl;  // Output: 1 (true), divisible by 3 exclusively
    cout << test(7) << endl;  // Output: 1 (true), divisible by 7 exclusively
    cout << test(21) << endl; // Output: 0 (false), divisible by both 3 and 7

    return 0; // Return 0 to indicate successful completion
}

Sample Output:

1
1
0

Visual Presentation:

Flowchart:

For more Practice: Solve these Related Problems:

• Write a C++ program to check if a non-negative number is a multiple of 3 or 7, but not a multiple of both, and print true or false.
• Write a C++ program that reads a number and verifies it is divisible by either 3 or 7 exclusively, using logical operators to avoid dual multiples.
• Write a C++ program to determine if an input number is a multiple of 3 or 7 while ensuring it is not divisible by both simultaneously.
• Write a C++ program that checks a number’s divisibility by 3 and 7 separately and outputs true only if exactly one of these conditions holds.

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