C++ Exercises: Get the day of the week from a given date
C++ Date: Exercise-2 with Solution
Write a C++ program to get the day of the week from a given date. Return the day as a string. The format of the day is MM/DD/YYYY.
- YYYY denotes the 4 digit year.
- MM denotes the 2 digit month.
- DD denotes the 2 digit day.
Note: Assume the week starts on Monday.
Sample Solution:
C++ Code:
#include <iostream>
#include <string>
#include<vector>
using namespace std;
std::string day_of_the_week(std::string day) {
int month = stoi(day.substr(0,2));
int _day = stoi(day.substr(3,2));
int year = stoi(day.substr(6,4));
vector<int> days={31,28,31,30,31,30,31,31,30,31,30,31};
vector<string> dates={"Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"};
int d = _day;
for(int i = 0; i < month-1; i++) d += days[i];
if ( ( ( year%4 == 0 && year%100 != 0) || year%400 == 0) && month > 2) d++;
for(int i = 1971; i < year; i++) {
if ( ( i%4 == 0 && i%100 != 0) || i%400 == 0) d += 366;
else d += 365;
}
string result = dates[ ( d%7 + 3 ) % 7];
return result;
}
int main(){
string date1, date2, date3, date4;
date1= "02/05/1980";
cout << "Date: " << date1 << " Day of the week: "<<day_of_the_week(date1);
date2= "01/24/1990";
cout << "\nDate: " << date2 << " Day of the week: "<<day_of_the_week(date2);
date3= "01/05/2019";
cout << "\nDate: " << date3 << " Day of the week: "<<day_of_the_week(date3);
date4= "11/17/2022";
cout << "\nDate: " << date4 << " Day of the week: "<<day_of_the_week(date4);
}
Sample Output:
Date: 02/05/1980 Day of the week: Tuesday Date: 01/24/1990 Day of the week: Wednesday Date: 01/05/2019 Day of the week: Saturday Date: 11/17/2022 Day of the week: Thursday
N.B.: The result may vary for your current system date and time.
Flowchart:

C++ Code Editor:
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