C++ Exercises: Find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n
C++ For Loop: Exercise-11 with Solution
Write a program in C++ to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.
Pictorial Presentation:

Sample Solution :-
C++ Code :
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
double sum = 0, a;
int n, i;
cout << "\n\n Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n:\n";
cout << "----------------------------------------------------------------\n";
cout << " Input the value for nth term: ";
cin >> n;
for (i = 1; i <= n; ++i)
{
a = 1 / pow(i, i);
cout << "1/" << i << "^" << i << " = " << a << endl;
sum += a;
}
cout << " The sum of the above series is: " << sum << endl;
}
Sample Output:
Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n: ---------------------------------------------------------------- Input the value for nth term: 5 1/1^1 = 1 1/2^2 = 0.25 1/3^3 = 0.037037 1/4^4 = 0.00390625 1/5^5 = 0.00032 The sum of the above series is: 1.29126
Flowchart:

C++ Code Editor:
Contribute your code and comments through Disqus.
Previous: Write a program in C++ to find the sum of digits of a given number.
Next: Write a program in C++ to calculate the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n).
What is the difficulty level of this exercise?
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- JavaScript String Exercises
- JavaScript HTML Form Validation
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join