C++ Exercises: Calculate the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)
C++ For Loop: Exercise-12 with Solution
Write a program in C++ to calculate the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n).
Pictorial Presentation:

Sample Solution :-
C++ Code :
#include <iostream>
using namespace std;
int main()
{
int i, n, sum = 0;
cout << "\n\n Find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n):\n";
cout << "------------------------------------------------------------------------------------\n";
cout << " Input the value for nth term: ";
cin >> n;
for (i = 1; i <= n; i++)
{
sum += i * i;
cout << i << "*" << i << " = " << i * i << endl;
}
cout << " The sum of the above series is: " << sum << endl;
}
Sample Output:
Find the sum of the series (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n): ----------------------------------------------------------------------- ------------- Input the value for nth term: 5 1*1 = 1 2*2 = 4 3*3 = 9 4*4 = 16 5*5 = 25 The sum of the above series is: 55
Flowchart:

C++ Code Editor:
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Previous: Write a program in C++ to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.
Next: Write a program in C++ to calculate the series (1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n).
What is the difficulty level of this exercise?
C++ Programming: Tips of the Day
Using C++ library in C code
You will need to write an interface layer in C++ that declares functions with extern "C":
extern "C" int foo(char *bar) { returnrealFoo(std::string(bar)); }
Then, you will call foo() from your C module, which will pass the call on to the realFoo() function which is implemented in C++.
If you need to expose a full C++ class with data members and methods, then you may need to do more work than this simple function example.
Ref: https://bit.ly/3clHy43
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