C++ Exercises: Display the n terms of even natural number and their sum
C++ For Loop: Exercise-21 with Solution
Write a program in C++ to display the n terms of even natural number and their sum.
Pictorial Presentation:

Sample Solution:-
C++ Code :
#include <iostream>
using namespace std;
int main()
{
int i, n, sum = 0;
cout << "\n\n Display n terms of even natural number and their sum:\n";
cout << "---------------------------------------------------------\n";
cout << " Input number of terms: ";
cin >> n;
cout << "\n The even numbers are: ";
for (i = 1; i <= n; i++)
{
cout << 2 * i << " ";
sum += 2 * i ;
}
cout << "\n The Sum of even Natural Numbers upto " << n << " terms: " << sum << endl;
}
Sample Output:
Display n terms of even natural number and their sum: --------------------------------------------------------- Input number of terms: 5 The even numbers are: 2 4 6 8 10 The Sum of even Natural Numbers upto 5 terms: 30
Flowchart:

C++ Code Editor:
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What is the difficulty level of this exercise?
C++ Programming: Tips of the Day
What is the usefulness of `enable_shared_from_this?
It enables you to get a valid shared_ptr instance to this, when all you have is this. Without it, you would have no way of getting a shared_ptr to this, unless you already had one as a member.
class Y: public enable_shared_from_this{ public: shared_ptr f() { return shared_from_this(); } } int main() { shared_ptr p(new Y); shared_ptr q = p->f(); assert(p == q); assert(!(p < q || q < p)); // p and q must share ownership }
The method f() returns a valid shared_ptr, even though it had no member instance. Note that you cannot simply do this:
class Y: public enable_shared_from_this{ public: shared_ptr f() { return shared_ptr (this); } }
The shared pointer that this returned will have a different reference count from the "proper" one, and one of them will end up losing and holding a dangling reference when the object is deleted.
Ref : https://bit.ly/3pwVzzz
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