﻿ C++ : Display the n terms of odd natural number, their sum

# C++ Exercises: Display the n terms of odd natural number and their sum

## C++ For Loop: Exercise-20 with Solution

Write a C++ program that displays the sum of n odd natural numbers.

Visual Presentation:

Sample Solution:-

C++ Code :

``````#include <iostream> // Include input-output stream header

using namespace std; // Using standard namespace to avoid writing std::

int main() // Start of the main function
{
int i, n, sum = 0; // Declaration of integer variables 'i' (loop counter), 'n' (user input for the number of terms), 'sum' (sum of odd natural numbers)

cout << "\n\n Display n terms of odd natural number and their sum:\n"; // Display message on the console
cout << "---------------------------------------------------------\n";
cout << " Input number of terms: "; // Prompt the user to input the number of terms
cin >> n; // Read the input value as the number of terms

cout << " The odd numbers are: "; // Display message indicating the list of odd numbers

for (i = 1; i <= n; i++) // Loop for 'n' terms
{
cout << 2 * i - 1 << " "; // Print the odd numbers by formula 2 * 'i' - 1
sum += 2 * i - 1; // Add the odd number to the sum variable
}

cout << "\n The Sum of odd Natural Numbers up to " << n << " terms: " << sum << endl; // Display the sum of odd numbers up to 'n' terms
}
``````

Sample Output:

```Display n terms of odd natural number and their sum:
---------------------------------------------------------
Input number of terms: 5
The odd numbers are: 1 3 5 7 9
```

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