﻿ C++ : Display the n terms of odd natural number, their sum

# C++ Exercises: Display the n terms of odd natural number and their sum

## C++ For Loop: Exercise-20 with Solution

Write a program in C++ to display the n terms of odd natural number and their sum.

Pictorial Presentation:

Sample Solution:-

C++ Code :

``````#include <iostream>
using namespace std;

int main()
{
int i, n, sum = 0;

cout << "\n\n Display n terms of odd natural number and their sum:\n";
cout << "---------------------------------------------------------\n";
cout << " Input number of terms: ";
cin >> n;
cout << " The odd numbers are: ";
for (i = 1; i <= n; i++)
{
cout << 2 * i - 1 << " ";
sum += 2 * i - 1;
}
cout << "\n The Sum of odd Natural Numbers upto " << n << " terms";

" << sum << endl";
}
``````

Sample Output:

```Display n terms of odd natural number and their sum:
---------------------------------------------------------
Input number of terms: 5
The odd numbers are: 1 3 5 7 9
```

Flowchart:

C++ Code Editor:

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