C++ Exercises: Check whether a number is Lychrel number or not

C++ Numbers: Exercise-11 with Solution

Write a program in C++ to check whether a number is a Lychrel number or not.

Pictorial Presentation:

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;


long long int numReverse(long long int number)
{
    long long int rem = 0;
    while (number > 0)
    {
    rem = (rem * 10) + (number % 10);
        number = number / 10;
    }
    return rem;
}
bool is_Palindrome(long long int num)
{
    return (num == numReverse(num));
}
bool isLychrel(int num, const int iterCount = 500)
{
    long long int temp = num;
    long long int rev;
    for (int i = 0; i < iterCount; i++)
    {
        rev = numReverse(temp);
        if (is_Palindrome(rev + temp))
            return false;
        temp = temp + rev;
    }
    return true;
}
int main()
{
int lyno;
bool l;
 cout << "\n\n Check whether a given number is a Lychrel number: \n";
 cout << " ------------------------------------------------------\n";
 cout << " Input a number: ";
 cin >> lyno;
    l = isLychrel(lyno);
    if (l==0)
    {
        cout <<" The number is not a Lychrel number."<<endl;
    }
    else
    if(l==1)
    {
        cout<<" The number is a Lychrel number."<<endl;;
    }
    return 0;
}

Sample Output:

Check whether a given number is a Lychrel number:                                                   
 ------------------------------------------------------                                              
 Input a number: 196                                                                                 
 The number is a Lychrel number.

Flowchart:

C++ Code Editor:

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