C++ Exercises: Find Disarium numbers between 1 to 1000

C++ Numbers: Exercise-19 with Solution

Write a C++ program to find Disarium numbers between 1 and 1000.

Visual Presentation:

Sample Solution:

C++ Code :

 #include<bits/stdc++.h> // Include necessary libraries
using namespace std; // Use the standard namespace

// Function to count the number of digits in a number
int DigiCount(int n)
{
    int ctr_digi = 0; // Counter for digits initialized to 0
    int tmpx = n; // Temporary variable to store the number

    // Loop to count the digits by dividing the number by 10 until it becomes zero
    while (tmpx)
    {
        tmpx = tmpx / 10; // Divide the number by 10
        ctr_digi++; // Increment digit counter
    }
    return ctr_digi; // Return the count of digits in the number
}

// Function to check if a number is a Disarium Number
bool chkDisarum(int n)
{
    int ctr_digi = DigiCount(n); // Calculate the count of digits in the number
    int s = 0; // Initialize sum of powered digits to 0
    int x = n; // Temporary variable to store the number
    int pr; // Variable to store digits extracted from the number

    // Loop to calculate the sum of powered digits
    while (x)
    {
        pr = x % 10; // Extract the last digit of the number
        s = s + pow(pr, ctr_digi--); // Add the powered digit to the sum
        x = x / 10; // Remove the last digit from the number
    }
    return (s == n); // Return true if the sum of powered digits is equal to the original number
}

// Main function
int main()
{
    int i; // Loop variable

    cout << "\n\n Find Disarium Numbers between 1 to 1000: \n"; // Display message about the program
    cout << " ---------------------------------------------\n";
    cout << " The Disarium numbers are: "<<endl; // Display header for Disarium numbers

    // Loop through numbers from 1 to 1000 to find and display Disarium numbers
    for(i = 1; i <= 1000; i++)
    {
        if (chkDisarum(i)) // Check if the number is a Disarium number
            cout << i << " "; // Display Disarium number if found
    }	
    cout << endl; // Print newline after displaying all Disarium numbers
    return 0; // Return 0 to indicate successful execution
}

Sample Output:

 Find Disarium Numbers between 1 to 1000:                                                            
 ---------------------------------------------                                                       
 The Disarium numbers are:                                                                           
1 2 3 4 5 6 7 8 9 89 135 175 518 598

Flowchart:

C++ Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a program in C++ to check whether a number is Disarium or not.
Next: Write a program in C++ to check if a number is Harshad Number or not.