C#: Get only the odd values from a given array of integers

Last update on August 22 2025 12:42:31 (UTC/GMT +8 hours)

Write a C# Sharp program to get only odd values from a given integer array.

Sample Solution:-

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    class Program
    {
        static void Main(string[] args)
        {
            // Define an array of integers
            int[] nums = { 1, 2, 3, 5, 4, 2, 3, 4 };

            // Call the 'test' method to filter odd values from the 'nums' array
            int[] result = test(nums);

            // Display the odd values of the 'nums' array
            Console.WriteLine("Only the odd values of the said array:");
            Array.ForEach(result, Console.WriteLine);

            // Define another array of integers
            int[] nums1 = { 2, 4, 2, 6, 4, 8 };

            // Call the 'test' method to filter odd values from the 'nums1' array
            result = test(nums1);

            // Display the odd values of the 'nums1' array
            Console.WriteLine("Only the odd values of the said array:");
            Array.ForEach(result, Console.WriteLine);
        }

        // Method to filter odd values from an integer array
        public static int[] test(int[] arr)
        {
            // Use LINQ to filter odd values from the input array and convert the result back to an array
            return arr.Where(n => n % 2 != 0).ToArray();
        }
    }
}

Sample Output:

Only the odd values of the said array:
1
3
5
3
Only the odd values of the said array:

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