C#: Count the number of two 5's are next to each other in an array of integers

C# Sharp Basic Algorithm: Exercise-38 with Solution

Write a C# Sharp program to count the number of two 5's next to each other in an array of integers. Count the situation where the second 5 is actually a 6.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    // Class declaration
    class Program
    {
        // Main method - entry point of the program
        static void Main(string[] args)
        {
            // Calling the 'test' method with different integer arrays
            Console.WriteLine(test(new[] { 5, 5, 2 }));         // Output: 1
            Console.WriteLine(test(new[] { 5, 5, 2, 5, 5 }));  // Output: 2
            Console.WriteLine(test(new[] { 5, 6, 2, 9 }));     // Output: 0
            Console.ReadLine(); // Keeping the console window open
        }

        // Method to count occurrences of specific number patterns in an integer array
        public static int test(int[] numbers)
        {
            var ctr = 0; // Counter to track occurrences
            for (var i = 0; i < numbers.Length - 1; i++) // Loop through the array till the second-to-last element
            {
                // Check for the pattern '5, 5' or '5, 6'
                if (numbers[i].Equals(5) && (numbers[i + 1].Equals(5) || numbers[i + 1].Equals(6)))
                {
                    ctr++; // Increment the counter if the pattern is found
                }
            }
            return ctr; // Return the count of occurrences
        }
    }
}

Sample Output:

1
2
1

Flowchart:

C# Sharp Code Editor:

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