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C# Sharp Basic Algorithm Exercises: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x


C# Sharp Basic Algorithm: Exercise-54 with Solution

Write a C# Sharp program to compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x. If the sum has more digits than x then return x without y.

Pictorial Presentation:

C# Sharp: Basic Algorithm Exercises - Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x.

Sample Solution:-

C# Sharp Code:

using System;
using System.Linq;
namespace exercises
{
   class Program
    {       
        static void Main(string[] args)
        {
            Console.WriteLine(test(4, 5));
            Console.WriteLine(test(7, 4));
            Console.WriteLine(test(10, 10));
            Console.ReadLine();
        }
        
        public static int test(int x, int y)
        {
           return (x + y).ToString().Length > x.ToString().Length ? x : x + y;
        }
    }
}

Sample Output:

9
7
20

Flowchart:

C# Sharp: Flowchart: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x.

C# Sharp Code Editor:

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Previous: Write a C# Sharp program to check two given integers, each in the range  10..99. Return true if a digit appears in both numbers, such as the 3 in 13 and 33
Next: Write a C# Sharp program to compute the sum of three given integers. If the two values are same return the third value.

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