C#: Compute the sum of the three integers. If one of the values is 13 then do not count it and its right towards the sum

C# Sharp Basic Algorithm: Exercise-56 with Solution

Sum of Three Integers Ignoring 13 and Right

Write a C# Sharp program to compute the sum of the three integers. If one of the values is 13 then do not count it and its right towards the sum.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Import the System namespace which contains fundamental types and base classes
using System.Linq; // Import the LINQ namespace for LINQ functionality

namespace exercises // Define a namespace called 'exercises'
{
    class Program // Define a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Output the result of test function with different sets of three integers as arguments
            Console.WriteLine(test(4, 5, 7)); // Test with integers 4, 5, and 7
            Console.WriteLine(test(7, 4, 12)); // Test with integers 7, 4, and 12
            Console.WriteLine(test(10, 13, 12)); // Test with integers 10, 13, and 12
            Console.WriteLine(test(13, 12, 18)); // Test with integers 13, 12, and 18
            Console.ReadLine(); // Wait for user input before closing the console window
        }

        // Function definition of test function that takes three integers 'x', 'y', and 'z' and returns an integer
        public static int test(int x, int y, int z)
        {
            if (x == 13) return 0; // If 'x' is equal to 13, return 0
            if (y == 13) return x; // If 'y' is equal to 13, return 'x'
            if (z == 13) return x + y; // If 'z' is equal to 13, return the sum of 'x' and 'y'
            return x + y + z; // If none of the above conditions match, return the sum of 'x', 'y', and 'z'
        }
    }
}

Sample Output:

16
23
10
0

Flowchart:

C# Sharp Code Editor:

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