C#: Create a new array of integers and length 1 or more

C# Sharp Basic Algorithm: Exercise-99 with Solution

Write a C# Sharp program to create an array of integers with a length of 1 or more. The array length will be double the given array length. All the elements are 0 except the first element which is equal to the given array.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {
            // Calling the 'test' method with an integer array as an argument and assigning the result to the 'item' array
            int[] item = test(new[] { 10, 20, -30, -40, 30 });

            // Outputting text to indicate the start of displaying the new array
            Console.Write("New array: ");

            // Looping through each element of the 'item' array and displaying them
            foreach (var i in item)
            {
                Console.Write(i.ToString() + " "); // Displaying each element of the 'item' array separated by a space
            }
        }        

        // Method to create a new array with double the length of the input array and copies the first element into the new array
        public static int[] test(int[] nums)
        {
            int elements = nums.Length * 2; // Calculating the number of elements needed for the new array
            int[] doubleNums = new int[elements]; // Creating a new array with double the length of the input array

            doubleNums[0] = nums[0]; // Copying the first element of 'nums' to the first element of 'doubleNums'
            return doubleNums; // Returning the new array 'doubleNums'
        } 
    }
}

Sample Output:

New array: 10 0 0 0 0 0 0 0 0 0

Flowchart:

C# Sharp Code Editor:

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